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Home Page > Math > Calculus

Improper Integral Calculator

Infinite bounds and singularities require limits rather than ordinary endpoint substitution. MiniWebtool’s Improper Integral Calculator evaluates Type I and Type II cases, displaying the convergence result and the steps used to reach it.

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Improper Integral CalculatorTry it now — free ▼
Improper integral = limit as b → ∞: 1/x² settles at 1, 1/x never does

Enter a function and the bounds (use infinity for an unbounded end) to see whether the integral converges, with the steps.

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INTEGRAL PREVIEW
$$\int_{0}^{\infty} f(x) \, dx$$
Supports: x^2, sqrt(x), sin(x), cos(x), exp(x), ln(x), pi, e
Finite lower bound
Upper bound is ∞

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About Improper Integral Calculator

The Improper Integral Calculator evaluates integrals that involve infinite limits or discontinuities in the integrand — cases where standard integration techniques cannot be directly applied. These integrals arise frequently in probability, physics, engineering, and advanced mathematics. This calculator uses adaptive numerical methods to determine whether an improper integral converges or diverges, and provides precise numerical approximations along with animated visualizations and convergence analysis.

At a Glance

Improper Integral Calculator evaluates integrals with infinite limits or a discontinuity and reports whether they converge or diverge. It gives a numerical value, a convergence table and a step-by-step solution.

Improper Integral Calculator: features at a glance
FeatureWhat you getGood for
Integral typesType I with an infinite upper, lower or both limits, and Type II with a discontinuity at a bound.Calculus courses covering convergence and divergence
InputsEnter f(x), pick the type, and set the bounds. Infinite limits need only the finite bound.Checking a textbook integral
Numerical methodAdaptive Simpson's quadrature approximates the value. Known exact values, such as the Gaussian integral, are shown for comparison.Getting a numerical answer where no simple antiderivative exists
Convergence tableShows how the value settles as the truncation limit increases.Seeing whether the value stabilizes or grows
Animated areaAn area plot with Static and Animate Fill views.Picturing the area under the curve
Example buttonsOne-click examples such as 1/x^2 on [1, infinity), 1/x on [1, infinity), the Gaussian and 1/sqrt(x) on [0, 1].Seeing a convergent and a divergent case side by side
StepsA step-by-step solution accompanies each result.Following the limit setup in class work

Types of Improper Integrals

→∞
Type I: Infinite Upper Limit
The integral \( \int_a^{\infty} f(x)\,dx \) is evaluated as \( \lim_{t\to\infty} \int_a^t f(x)\,dx \). Example: \( \int_1^{\infty} \frac{1}{x^2}\,dx = 1 \)
-∞→
Type I: Infinite Lower Limit
The integral \( \int_{-\infty}^b f(x)\,dx \) is evaluated as \( \lim_{t\to -\infty} \int_t^b f(x)\,dx \). Example: \( \int_{-\infty}^0 e^x\,dx = 1 \)
±∞
Type I: Both Limits Infinite
Split at a convenient point: \( \int_{-\infty}^{\infty} f(x)\,dx = \int_{-\infty}^0 f(x)\,dx + \int_0^{\infty} f(x)\,dx \). Both halves must converge independently.
⚡
Type II: Discontinuity
When f(x) has a vertical asymptote at a bound, approach it as a limit: \( \lim_{\varepsilon\to 0^+} \int_{a+\varepsilon}^b f(x)\,dx \). Example: \( \int_0^1 \frac{1}{\sqrt{x}}\,dx = 2 \)

How to Use the Improper Integral Calculator

  1. Enter your function — Type f(x) using standard notation. Examples: 1/x^2, exp(-x^2), 1/(1+x^2), 1/sqrt(x).
  2. Select the integral type — Choose whether the integral has an infinite upper limit, infinite lower limit, both limits infinite, or a discontinuity at one of the bounds.
  3. Set the finite bound(s) — Enter the required bounds. For infinite limits, only the finite bound is needed. For discontinuity types, enter both bounds.
  4. Click Evaluate — The calculator determines convergence or divergence, shows the numerical value (if convergent), provides an animated area visualization, a convergence table showing how the value stabilizes as the truncation limit increases, and a step-by-step solution.

The p-Test for Convergence

One of the most important convergence tests for improper integrals:

Improper Integral Calculator: The p-Test for Convergence
IntegralConditionResult
\( \int_1^{\infty} \frac{1}{x^p}\,dx \)p > 1Converges to \( \frac{1}{p-1} \)
\( \int_1^{\infty} \frac{1}{x^p}\,dx \)p ≤ 1Diverges
\( \int_0^1 \frac{1}{x^p}\,dx \)p < 1Converges to \( \frac{1}{1-p} \)
\( \int_0^1 \frac{1}{x^p}\,dx \)p ≥ 1Diverges

Famous Improper Integrals

Improper Integral Calculator: Famous Improper Integrals
IntegralExact ValueName/Application
\( \int_{-\infty}^{\infty} e^{-x^2}\,dx \)\( \sqrt{\pi} \approx 1.7725 \)Gaussian integral (probability, physics)
\( \int_{-\infty}^{\infty} \frac{1}{1+x^2}\,dx \)\( \pi \approx 3.1416 \)Cauchy/Lorentz distribution
\( \int_0^{\infty} e^{-x}\,dx \)1Exponential decay
\( \int_0^{\infty} \frac{\sin(x)}{x}\,dx \)\( \frac{\pi}{2} \approx 1.5708 \)Dirichlet integral (signal processing)
\( \int_0^1 \frac{1}{\sqrt{x}}\,dx \)2Type II, p-test with p = 1/2

Common Applications

Frequently Asked Questions

What is an improper integral?
An improper integral is an integral where either one or both limits of integration are infinite, or the integrand has a discontinuity (vertical asymptote) within the interval. They are evaluated as limits: the infinite bound is replaced by a variable that approaches infinity, or the discontinuity is approached from the appropriate side.
How do you determine if an improper integral converges or diverges?
An improper integral converges if the limit exists and is finite. It diverges if the limit is infinite or does not exist. Common convergence tests include the p-test (integral of 1/x^p converges for p > 1), the comparison test, and the limit comparison test. This calculator determines convergence numerically by evaluating with increasing truncation limits and checking if the values stabilize.
What is the difference between Type I and Type II improper integrals?
Type I improper integrals have one or both infinite limits of integration (e.g., integral from 1 to infinity). Type II improper integrals have a discontinuity in the integrand within the interval (e.g., integral of 1/sqrt(x) from 0 to 1, where the function is undefined at x = 0).
What is the Gaussian integral?
The Gaussian integral is the integral of e^(-x²) from negative infinity to positive infinity, which equals the square root of pi (approximately 1.7725). It is one of the most famous improper integrals and is fundamental in probability theory, statistics, and physics. It cannot be evaluated using elementary antiderivatives.
Can this calculator find exact symbolic answers?
This calculator uses numerical methods (adaptive Simpson's quadrature) to approximate the value of improper integrals. It provides high-precision numerical results and identifies convergence or divergence. For some famous integrals like the Gaussian integral, it also displays the known exact value for comparison.

Reference this content, page, or tool as:

"Improper Integral Calculator" at https://MiniWebtool.com/improper-integral-calculator/ from MiniWebtool, https://MiniWebtool.com/

by miniwebtool team. Updated: 2026-04-05

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